Transitional Δv = ( ( 5000 Δv atm - 2500 Δv required to escape Kerbin atmosphere ) / 5000 Δv atm ) X 6000 Δv vac + 2500 Δv required to escape Kerbin atmosphere = Total Δv of 5500 m/s See also KSP 1.2 Debug/Cheat Menu - Technical Support (PC, Modded. Single stage with total atmospheric Δv of 5000 m/s, and rated 6000 Δv in vacuum. Finding Keq Keq products reactants You can have Kc, Kp, Ksp, Ka, Kb These are the same as Keq. True Δv = ( ( Total Δv in atmosphere - 2500 m/s) / Total Δv in atmosphere ) X Total Δv in vacuum + 2500 True Δv = ( ( Δv atm - 2500 ) / Δv atm ) * Δv vac + 2500 Single stage with total atmospheric v of 5000 m/s, and rated 6000 v in vacuum. Δ v = l n ( M s t a r t M e n d ) ⋅ I s p ⋅ 9.81 m s 2
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